Reverse an integer using math operations.

Build up a new number m by multiplying by 10 and dividing the original number n by 10 until n is 0. The digit in the ‘ones’ position is taken from the original and added to the new number at each iteration.

int reverse(int n) { int m = 0 while (n) { int r = n % 10 m = m * 10 + r n = n / 10 } return m }